A store manager wants to determine how much to pay her employees. The number of hours the employees work is X and the hourly wage they are paid is Y. The store manager is willing to pay the employees a wage given by the equation 10y -30x =20. The business owner states that the employee should be paid a wage given by the equation 6y + 30x = 60. If the two equations were added, then simplified to determine hourly wage, Y, how much would the employees be paid?

Question

A store manager wants to determine how much to pay her employees. The number of hours the employees work is X and the hourly wage they are paid is Y. The store manager is willing to pay the employees a wage given by the equation 10y -30x =20. The business owner states that the employee should be paid a wage given by the equation 6y + 30x = 60. If the two equations were added, then simplified to determine hourly wage, Y, how much would the employees be paid?

Answer 1

To determine the hourly wage, we first need to add the two equations:

(10y - 30x) + (6y + 30x) = 20 + 60
Simplifying, we get:
16y = 80

Now, we can solve for y:
y = 80/16
y = 5

Therefore, the employees would be paid an hourly wage of $5.