troy is chasing his little brother kyle, but kyle got a 30 second head start. if kyle is traveling at 2 feet per second on his tricycle and troy is traveling at 5 feet per second on his skateboard, how many seconds will it be before troy catches kyle?
Let x be the number of seconds before Troy catches Kyle.
Since Kyle had a 30 second head start, he will have traveled 30*2 = 60 feet by the time Troy starts chasing him.
Since Troy is traveling at 5 feet per second, the distance he needs to cover to catch Kyle is 60 feet.
We can set up the equation: 5x = 60
Dividing both sides by 5, we get x = 12
So, it will take Troy 12 seconds to catch Kyle.
incorrect, the answer is not 12 seconds
Apologies for the mistake. Let's correct the solution.
Since Kyle had a head start of 30 seconds, he will have traveled 30 * 2 = 60 feet before Troy starts chasing him.
Now, we need to find the time it takes for Troy to catch up to Kyle.
Let the time taken to catch up be x seconds.
In x seconds, Troy will travel 5x feet and Kyle will travel 60 + 2x feet.
For Troy to catch up to Kyle, we need to solve the equation:
5x = 60 + 2x
Subtracting 2x from both sides, we get:
3x = 60
Dividing by 3:
x = 60 / 3
x = 20
Thus, it will take Troy 20 seconds to catch up to Kyle.