In a class of 242 students in biochemistry and anatomy, 86 likes physics only, 92 like biology only, 102 likes chemistry only, 46 likes both physics and biology and 32 likes noth physics and chemistry
A. Present the data in a Venn diagram.
B. Find the number of students who likes
i. Chemistry only
ii. Physics only
iii. Biology only
C. Find the number of students who like
I. Both physics and biology
ii. Both physics and chemistry
iii. None of the three courses
A.
In a Venn diagram, let P represent Physics, B represent Biology, and C represent Chemistry. The intersection of the three circles represents students who like all three subjects.
B.
i. Number of students who like Chemistry only = 102 - 32 = 70
ii. Number of students who like Physics only = 86 - 46 = 40
iii. Number of students who like Biology only = 92 - 46 = 46
C.
i. Number of students who like both Physics and Biology = 46
ii. Number of students who like both Physics and Chemistry = 86 - 46 = 40
iii. Number of students who like None = Total students - (Physics only + Biology only + Chemistry only + Both Physics and Biology + Both Physics and Chemistry + Both Biology and Chemistry + All three subjects) = 242 - (40 + 46 + 70 + 46 + 40 + 32 + x) = 242 - 274 + x = x - 32 = 32 - 32 = 0
Therefore, there are 0 students who like none of the three courses.