In a class of 32students,18 offer chemistry, 16 offer physics and 22 offer mathematics, 6 offer all three subjects ,3 offer. Chemistry and physics only, and 5 offer physics only, each students offers at least one subject. Find the no. of students who offer. 1Chemistry only . 2.only one subject. 3. Only two subject
Chemistry
Use a Venn diagram.
Start with the innermost data of 6 taking all 3 subjects.
Fill in the given intersections. The only one not given is the intersection of
Math and Chemistry only. Label that x.
Now you can fill in the Math-only as 22 - x - 11
and the Chemistry-only as 18 - x - 9
your Chemistry-only should have been 2 from the given data.
Now add up all the components:
22-x-11 + x + 6 + 5 + 2 + 18-x-9 = 32
x = 4
Now you know each component of your Venn, ....
I want to be best in Mathematics
A class at a college has 30 students and of these, 18 study business mathematics and 20 students study Micro-economics. Find the percentage of students who study business mathematics only?
Well, it seems like we're going to have some fun with numbers! Let's break it down step by step:
1. Chemistry Only:
We know that 18 students offer Chemistry, and 6 of them offer all three subjects. So to find the number of students who offer Chemistry only, we subtract the number of students who offer all three subjects from the total number of students who offer Chemistry:
18 - 6 = 12
Therefore, 12 students offer Chemistry only.
2. Only One Subject:
To find the number of students who offer only one subject, we need to add the number of students who offer Chemistry only, Physics only, and Mathematics only. We already found that 12 students offer Chemistry only. Now, let's figure out the other two subjects:
- We know that 5 students offer Physics only.
- We know that 22 students offer Mathematics, but we need to subtract the 6 who offer all three subjects.
So, the total number of students who offer only one subject is:
12 (Chemistry only) + 5 (Physics only) + (22 - 6) (Mathematics only) = 12 + 5 + 16 = 33
Therefore, 33 students offer only one subject.
3. Only Two Subjects:
To find the number of students who offer only two subjects, we need to subtract the number of students who offer all three subjects from the total number of students who offer two or more subjects. We know that 6 students offer all three subjects, so we subtract them from the total number of students who offer two or more subjects:
32 - 6 = 26
Therefore, 26 students offer only two subjects.
And that's the breakdown! Remember, don't use these numbers for your chemistry comedy routine unless you want to add a little confusion to the mix!
To find the number of students who offer Chemistry only, we first need to determine the number of students who offer Chemistry.
From the given information:
- 18 students offer Chemistry
- 6 students offer all three subjects (Chemistry, Physics, and Mathematics)
- 3 students offer Chemistry and Physics only
To find the number of students who offer Chemistry only, we need to subtract the number of students who offer all three subjects and the number of students who offer Chemistry and Physics only from the total number of students offering Chemistry.
Number of students who offer Chemistry only = Total number of students offering Chemistry - Number of students offering all three subjects - Number of students offering Chemistry and Physics only
Number of students who offer Chemistry only = 18 - 6 - 3
Number of students who offer Chemistry only = 9
Therefore, 9 students offer Chemistry only.
Now let's move on to finding the number of students who offer only one subject.
To find the number of students who offer only one subject, we need to sum up the number of students who offer each subject individually.
Number of students who offer only one subject = Number of students offering Chemistry only + Number of students offering Physics only + Number of students offering Mathematics only
Number of students who offer only one subject = 9 + 5 + 6
Number of students who offer only one subject = 20
Therefore, 20 students offer only one subject.
Finally, let's determine the number of students who offer only two subjects.
To find the number of students who offer only two subjects, we need to subtract the number of students who offer all three subjects from the total number of students offering two or more subjects.
Number of students who offer only two subjects = Total number of students offering two or more subjects - Number of students offering all three subjects
Number of students who offer only two subjects = 32 - 6
Number of students who offer only two subjects = 26
Therefore, 26 students offer only two subjects.