. A series circuit consisting of three resistors has a current of 3 amps, R1 =12kohtms. R2 = 60 ohms, R3= 80 ohms and the power dissipation of 180W, what is:
a. Total resistance,
b. Source voltage of the circuit,
C Power dissipation in each resistor of the circuit?
d. Voltage dropped in each resistor of the circuit?
e. If the current was increased to 4 amps, what would be voltage drop across each resistor?
f. What would have to be done to the circuit if the current increase to 4amps?
2.Four resistors are connected in parallel; R1 = 10 Ω. R 2 = 3KΩ , R3 = 1.5K Ω and R 4 = 560 Ω with the potential difference of 120v respectively, what is the equivalent resistance and IT and PT
3.?
4. Explain the following terms with their correct circuit diagram, formula and graph:
a. Total resistance in a series circuit is the sum of all individual resistances. Therefore, the total resistance in this circuit would be:
R_total = R1 + R2 + R3
R_total = 12 kohms + 60 ohms + 80 ohms
R_total = 12,140 ohms
b. To calculate the source voltage of the circuit, we use Ohm's Law:
V = I * R_total
V = 3 amps * 12,140 ohms
V = 36,420 volts
c. Power dissipation in each resistor can be calculated using the formula:
P = I^2 * R
For resistor R1: P1 = (3 amps)^2 * 12 kohms = 108 W
For resistor R2: P2 = (3 amps)^2 * 60 ohms = 540 W
For resistor R3: P3 = (3 amps)^2 * 80 ohms = 720 W
d. Voltage dropped in each resistor can be calculated using Ohm's Law:
For resistor R1: V1 = I * R1 = 3 amps * 12 kohms = 36,000 volts
For resistor R2: V2 = I * R2 = 3 amps * 60 ohms = 180 volts
For resistor R3: V3 = I * R3 = 3 amps * 80 ohms = 240 volts
e. If the current is increased to 4 amps, the voltage drop across each resistor would be:
For resistor R1: V1 = 4 amps * 12 kohms = 48,000 volts
For resistor R2: V2 = 4 amps * 60 ohms = 240 volts
For resistor R3: V3 = 4 amps * 80 ohms = 320 volts
f. If the current is increased to 4 amps, the power dissipation in each resistor would increase proportionally. The circuit may need to be reconfigured or have higher power rated resistors added to accommodate the increased current.
2. The equivalent resistance in a parallel circuit can be calculated using the formula:
1/R_eq = 1/R1 + 1/R2 + 1/R3 + 1/R4
1/R_eq = 1/10 ohms + 1/3 kohms + 1/1.5 kohms + 1/560 ohms
R_eq = 0.372 ohms
The total current (IT) in a parallel circuit is the sum of the currents through each branch, which is the same as the total current entering the parallel circuit. The total power dissipation (PT) in a parallel circuit is the sum of the power dissipated in each resistor.
3. Please provide the terms you would like explained in the context of a circuit diagram, formula, and graph.