Two machines at a factory are filling cans of soup. One machine has filled 92 cans of soup. It fills cans at a rate of 16 cans per minute. The second machine has filled 104 cans of soup. It fills cans at a rate of 13 cans per minute. Write and solve an equation to show when the two machines will have filled the same number of cans of soup.(1 point)
Let x be the number of minutes it takes for the two machines to fill the same number of cans of soup.
Machine 1: 92 + 16x
Machine 2: 104 + 13x
Setting these two expressions equal to each other:
92 + 16x = 104 + 13x
Solving for x:
16x - 13x = 104 - 92
3x = 12
x = 4
Therefore, the two machines will have filled the same number of cans of soup after 4 minutes.
Two machines at a factory are filling cans of soup. One machine has filled 92 cans of soup. It fills cans at a rate of 16 cans per minute. The second machine has filled 104 cans of soup. It fills cans at a rate of 13 cans per minute. Write and solve an equation to show when the two machines will have filled the same number of cans of soup.(1 point) Responses 92 + 16 x = 104 + 13 x ; x = 4 92 plus 16 x equals 104 plus 13 x ; x equals 4 104 + 16 x = 92 + 13 x ; x = 4 104 plus 16 x equals 92 plus 13 x ; x equals 4 92 − 16 x = 104 − 13 x ; x = − 4 92 minus 16 x equals 104 minus 13 x ; x equals negative 4 92 + 16 x = 104 + 13 x ; x = 6
The correct equation is:
92 + 16x = 104 + 13x
Solving for x:
16x - 13x = 104 - 92
3x = 12
x = 4
Therefore, the two machines will have filled the same number of cans of soup after 4 minutes. The correct answer is:
92 + 16x = 104 + 13x ; x = 4