Two machines at a factory are filling cans of soup. One machine has filled 92 cans of soup. It fills cans at a rate of 16 cans per minute. The second machine has filled 104 cans of soup. It fills cans at a rate of 13 cans per minute. Write and solve an equation to show when the two machines will have filled the same number of cans of soup
you give a different answer almost everytime
Let's assume t minutes as the time taken for both machines to fill the same number of cans of soup.
So the equation for the first machine can be written as:
Number of cans filled by first machine = 16t + 92
The equation for the second machine can be written as:
Number of cans filled by second machine = 13t + 104
Since we want to know the time when both machines will have filled the same number of cans of soup, we can set these two equations equal to each other and solve for t:
16t + 92 = 13t + 104
Simplifying the equation, we get:
3t = 12
So, t = 4 minutes
Therefore, both machines will have filled the same number of cans of soup in 4 minutes.
To find when the two machines will have filled the same number of cans of soup, we can set up an equation. Let's assume that after "t" minutes, the first machine has filled "92 + 16t" cans of soup, and the second machine has filled "104 + 13t" cans of soup.
So, the equation becomes:
92 + 16t = 104 + 13t
To solve this equation, we need to isolate the variable "t" on one side. We can do this by subtracting 13t from both sides and then subtracting 92 from both sides:
92 + 16t - 13t = 104 + 13t - 13t - 92
3t = 12
Now, divide both sides of the equation by 3 to solve for "t":
3t/3 = 12/3
t = 4
The two machines will have filled the same number of cans of soup after 4 minutes.