Translate triangle ABC left 3, down 5 and then perform a dilation of 4 around the center at the origin.
Point B is (2,6)
point A (2,3
point c is (4,3)
After translating triangle ABC left 3, down 5 and dilation of 4 around the center at the origin, the new coordinates for the points would be:
Point B: (2-3)*4, (6-5)*4 = (-4,4)
Point A: (2-3)*4, (3-5)*4 = (-4, -8)
Point C: (4-3)*4, (3-5)*4 = (4, -8)
Can you break it down some more?
please
Of course!
First, let's translate triangle ABC left 3 units and down 5 units. This means subtracting 3 from the x-coordinates of all points of the triangle and subtracting 5 from the y-coordinates.
New coordinates after translation:
Point B: (2-3, 6-5) = (-1, 1)
Point A: (2-3, 3-5) = (-1, -2)
Point C: (4-3, 3-5) = (1, -2)
Next, let's perform a dilation of 4 around the center at the origin. This means multiplying each coordinate by 4.
New coordinates after dilation:
Point B: (-1*4, 1*4) = (-4, 4)
Point A: (-1*4, -2*4) = (-4, -8)
Point C: (1*4, -2*4) = (4, -8)
After applying both operations, the new positions of the points in triangle ABC are:
Point A (-4, -8)
Point B (-4, 4)
Point C (4, -8)