Use the formula for the area of a triangle to determine the area of a triangle with base equal to 13 yards and height equal to 5 yards. (1 point) Responses 18 square yards 18 square yards 65 square yards 65 square yards 27.5 square yards 27.5 square yards 32.5 square yards
The formula for the area of a triangle is:
Area = 1/2 * base * height
Plugging in the values given:
Area = 1/2 * 13 * 5
Area = 1/2 * 65
Area = 32.5 square yards
Therefore, the area of the triangle is 32.5 square yards.
There is a triangle. Its hypotenuse is 15 ae long. The triangle has a line through it, the line is called 'x'. The line makes it look like there is a big and small triangle. One of the sides of the small triangle makes up the main triangle's hypotenuse. This side measures 8 ae.
Question: HOW MANY ae does the line called 'x' measure??
To solve this problem, we can use the Pythagorean Theorem which states that in a right-angled triangle, the square of the length of the hypotenuse is equal to the sum of the squares of the other two sides.
Let x be the length of side x.
Using the Pythagorean Theorem:
x^2 + 8^2 = 15^2
x^2 + 64 = 225
x^2 = 225 - 64
x^2 = 161
x = √161
Therefore, the length of the line x is approximately 12.69 ae.
There is a triangle. Its hypotenuse is 23 ae long. The triangle has a line through it, the line is called 'x'. The line makes it look like there is a big and small triangle. One of the sides of the small triangle makes up the main triangle's hypotenuse. This side measures 8 ae.
Question: HOW MANY ae does the line called 'x' measure??
To solve this problem, we can once again use the Pythagorean Theorem which states that in a right-angled triangle, the square of the length of the hypotenuse is equal to the sum of the squares of the other two sides.
Let x be the length of side x.
Using the Pythagorean Theorem:
x^2 + 8^2 = 23^2
x^2 + 64 = 529
x^2 = 529 - 64
x^2 = 465
x = √465
Therefore, the length of the line x is approximately 21.59 ae.
LOL, don't base your measurements on the classic way.
You only have the hypotenuse and a line cutting a triangle in two. 23 and 8 are on the same line. Here's something for you: 23-8=15. 15 is also on the same line as 8 and 23.
So you only know the hypotenuse, the numbers composing it, and an unknown 'x'.
RE-calculate the 'x'.
I apologize for the error in my previous responses. Let's re-calculate the length of the line x using the given information:
The length of one segment is 8 and the other segment is 15 (23-8=15), which is the hypotenuse. Let's name these segments with their respective lengths.
Let a be 8 (smallest segment)
Let b be 15 (hypotenuse)
Let x be the unknown segment
According to the given information:
a^2 + x^2 = b^2
8^2 + x^2 = 15^2
64 + x^2 = 225
x^2 = 225 - 64
x^2 = 161
x = √161
x ≈ 12.69
Therefore, the length of the line x is approximately 12.69 ae. Thank you for pointing out the mistake.