engineers are developing new types of guns that might someday be used to launch satellites as if they were bullets. one such gun can give a small object starting at rest a velocity of 3.5km/s moving it through only 2.0cm
what acceleration does the gun give this object
over what time interval does this take place
To find the acceleration of the object, we can use the equation of motion:
v^2 = u^2 + 2as
where:
v = final velocity = 3.5 km/s = 3500 m/s
u = initial velocity = 0 m/s (object starting at rest)
a = acceleration
s = displacement = 0.02 m
Plugging in the values, we get:
(3500)^2 = (0)^2 + 2 * a * 0.02
12250000 = 0.04a
a = 306250 m/s^2
So, the acceleration the gun gives the object is 306250 m/s^2.
To find the time interval, we can use the equation:
v = u + at
Plugging in the values we have:
3500 = 0 + 306250 * t
t = 0.01147 seconds
Therefore, the gun gives the object an acceleration of 306250 m/s^2 over a time interval of 0.01147 seconds.