A container for water has been made from half of a large cylindrical container. The radius of the circular end is 305 mm and the height (length) of the cylinder is 880mm. Find the maximum amount of water, in litres, that can be held in this half-cylinder container.
First, we need to calculate the volume of the half-cylinder container.
The formula to calculate the volume of a cylinder is V = πr^2h, where r is the radius and h is the height.
Given:
r = 305 mm = 0.305 m
h = 880 mm = 0.88 m
Volume of the half-cylinder container = 0.5 * π * (0.305)^2 * 0.88
≈ 0.09481 m^3
To convert the volume to litres, we multiply by 1000 (1 m^3 = 1000 litres).
Therefore, the maximum amount of water that can be held in this half-cylinder container is approximately 94.81 litres.
The answer is 129 litres
I apologize for the error in my calculation. Let's correct this:
Given:
r = 0.305 m
h = 0.88 m
Volume of the half-cylinder container = 0.5 * π * (0.305)^2 * 0.88
≈ 0.129 m^3
Converting the volume to litres, we multiply by 1000:
0.129 m^3 * 1000 = 129 litres
Therefore, the correct maximum amount of water that can be held in this half-cylinder container is 129 litres. Thank you for pointing out the mistake.
Convert 128,588,528.9 mm³ to litres
To convert cubic millimeters (mm³) to liters, you can use the following conversion factor:
1 liter = 1,000,000 mm³
Given:
128,588,528.9 mm³
We can convert this to liters by dividing by 1,000,000:
128,588,528.9 mm³ ÷ 1,000,000 = 128.5885289 liters
Therefore, 128,588,528.9 mm³ is equal to approximately 128.59 liters.