2 machines at a factory are filling cans of soup. One machine has already filled 280 cans of soup, and it fills cans at a rate of 15 per minute. The second machine has already filled 210 cans of soup, and fills cans at a rate of 12 per minute. Write an equation to show when the 2 machines will have filled the same number of cans of soup. use x as your variable.

The equation to show when the 2 machines will have filled the same number of cans of soup is:

280 + 15x = 210 + 12x

try again please

Apologies for the incorrect equation. Let's try again.

Let's assume the time it takes for the two machines to fill the same number of cans is "x" minutes.

Machine 1 fills cans at a rate of 15 cans per minute. So in "x" minutes, it will fill 15x cans.

Machine 2 fills cans at a rate of 12 cans per minute. So in "x" minutes, it will fill 12x cans.

Since we want the two machines to have filled the same number of cans:

280 + 15x = 210 + 12x