Complete the following stepped-out solution to show that [8/9⋅(s⋅9/8)]+h is equivalent to s+h .%C2%A0(1 point) [8/9⋅(s⋅98)]+h %C2%A0 [(%C2%A089⋅)⋅s]+h Associative Property of Multiplication [%C2%A0⋅s]+h Inverse Property of Multiplication s+h Identity Property of Multiplication
To show that [8/9⋅(s⋅9/8)]+h is equivalent to s+h, we can follow these steps:
Step 1: Simplify the expression [8/9⋅(s⋅9/8)].
Using the associative property of multiplication, we can rearrange the terms within the parentheses:
[8/9⋅(s⋅9/8)] = [(8/9⋅9/8)⋅s]
Now simplify the expression within the parentheses:
[(8/9⋅9/8)⋅s] = [(1)⋅s]
Since any number multiplied by 1 is itself, we have:
[(1)⋅s] = s
Step 2: Substitute the result from step 1 into the original expression.
The original expression is [8/9⋅(s⋅9/8)]+h. Substituting s for [8/9⋅(s⋅9/8)], we get:
s + h
Therefore, [8/9⋅(s⋅9/8)]+h is indeed equivalent to s+h.