An illustration of a scatterplot graph shows x-axis ranging from 0 to 15 in increments of 1 and y-axis ranging from 0 to 75 in increments of 5. Multiple points are plotted and a line points upward to the right with an arrowhead on the top.
The line passes approximately through (0, 25), (1, 30), (2, 35) (7, 60), and (10, 75). 5 points are plotted to the line.
Write an equation in slope-intercept form of the trend line.
To find the equation of the trend line, we need to determine the slope and y-intercept.
We can find the slope using two points on the line, for example, (0, 25) and (2, 35).
slope (m) = (y2 - y1) / (x2 - x1)
= (35 - 25) / (2 - 0)
= 10 / 2
= 5
Next, we can substitute the slope and one point into the slope-intercept form of a linear equation to find the y-intercept.
Using the point (0, 25):
y = mx + b
25 = 5(0) + b
25 = b
Now we have the slope (m = 5) and y-intercept (b = 25), so the equation of the trend line in slope-intercept form is:
y = 5x + 25