Use the image to answer the question. An illustration of a scatterplot graph shows x-axis ranging from 0 to 10 in increments of 1 and y-axis ranging from 0 to 50 in increments of 10. Multiple points are plotted around a line that points downward to the right with an arrowhead on the bottom. The line passes approximately through left parenthesis 0 comma 45 right parenthesis, left parenthesis 2 comma 25 right parenthesis, left parenthesis 3 comma 15 right parenthesis, and left parenthesis 4.5 comma 0 right parenthesis. 13 points are plotted close to the line. Write an equation in slope-intercept form of the trend line.
To find the equation of the trend line, we first need to determine the slope and y-intercept.
By observing the points provided, we can see that the line passes approximately through the points (0, 45) and (4.5, 0).
The slope of the trend line can be calculated using the formula:
slope = (y2 - y1) / (x2 - x1)
slope = (0 - 45) / (4.5 - 0)
slope = -45 / 4.5
slope = -10
Using the point-slope form of a linear equation, we can determine the equation of the trend line:
y - y1 = m(x - x1)
Using the point (0, 45):
y - 45 = -10(x - 0)
y - 45 = -10x
y = -10x + 45
Therefore, the equation of the trend line in slope-intercept form is y = -10x + 45.
Use the image to answer the question. An illustration of a scatterplot graph shows x-axis ranging from 0 to 10 in increments of 1 and y-axis ranging from 0 to 30 in increments of 2. Multiple points are plotted around a line that points upward to the right with an arrowhead on the bottom. The line passes approximately through left parenthesis 0 comma 12 right parenthesis, left parenthesis 4 comma 16 right parenthesis, and left parenthesis 6 comma 18 right parenthesis. 12 points are plotted close to the line.Write an equation in slope-intercept form of the trend line.(1 point)
To find the equation of the trend line, we first need to determine the slope and y-intercept.
By observing the points provided, we can see that the line passes approximately through the points (0, 12), (4, 16), and (6, 18).
The slope of the trend line can be calculated using the formula:
slope = (y2 - y1) / (x2 - x1)
For the points (0, 12) and (4, 16):
slope = (16 - 12) / (4 - 0)
slope = 4 / 4
slope = 1
Using the point-slope form of a linear equation, we can determine the equation of the trend line:
y - y1 = m(x - x1)
Using the point (0, 12):
y - 12 = 1(x - 0)
y - 12 = x
y = x + 12
Therefore, the equation of the trend line in slope-intercept form is y = x + 12.