Two machines at a factory are filling cans of soup once machine has filled 92 cans of soup it fills cans a rate of 16 cans per minute the second machine has filled 104 cans of soup it fills cans at a rate of 13 cans per minute write and solve an equation to show when the two machines will have filled the same number of cans of souo

Question

Two machines at a factory are filling cans of soup once machine has filled 92 cans of soup it fills cans a rate of 16 cans per minute the second machine has filled 104 cans of soup it fills cans at a rate of 13 cans per minute write and solve an equation to show when the two machines will have filled the same number of cans of souo

Answer 1

Let's assume that the minutes it takes for the first machine to fill cans is represented by "x," and the minutes it takes for the second machine to fill cans is represented by "y."

We can write the equation for the first machine as: 92 + 16x, where 92 is the initial number of cans filled and 16x represents the cans filled based on the rate of 16 cans per minute.

We can write the equation for the second machine as: 104 + 13y, where 104 is the initial number of cans filled and 13y represents the cans filled based on the rate of 13 cans per minute.

To find when the two machines will have filled the same number of cans, we set the two equations equal to each other:

92 + 16x = 104 + 13y

Now, we can solve for x:
16x = 12 + 13y

x = (12 + 13y)/16

The solution is a specific value of y where the two machines will have filled the same number of cans. Without additional information, we cannot solve for a specific value.