Water was added to 120.0g of a salt.MCI2, to produce 60.0cm³ of a saturated solution at 25°c. It's solubility at 25°c is 8.0 moldm-³ calculate the mass of the salt which remained undissolved
(M=24 ,CI=35.5)
To solve this problem, we need to use the equation:
solubility = mass of salt dissolved/volume of solution
First, we need to find the volume of water added to the salt to produce the solution:
volume of water = volume of solution - volume of salt = 60.0 cm³ - x
Next, we can calculate the moles of salt dissolved using the solubility and volume of solution:
8.0 moldm-³ * (60.0 cm³ / 1000) dm³ = 0.48 moles
The molar mass of MCI2 is 24 + (2 * 35.5) = 95 g/mol. So, the mass of salt dissolved is:
mass of salt dissolved = 0.48 moles * 95 g/mol = 45.6 g
Finally, we can calculate the mass of the salt which remained undissolved:
mass of salt undissolved = mass of salt added - mass of salt dissolved
mass of salt undissolved = 120.0 g - 45.6 g = 74.4 g
Therefore, the mass of the salt which remained undissolved is 74.4 g.