At 20°C, a solution contains 120 g of NaNO3 in 100 g of water. Is this solution saturated, unsaturated, or supersaturated?
Ion know how to do dis thang.
No worries! Here's how to approach this problem:
1. Look up the solubility of NaNO3 in water at 50 degrees Celsius. Let's say the solubility is 102 grams of NaNO3 per 100 grams of water.
2. Calculate the maximum amount of NaNO3 that can dissolve in 100 grams of water at 50 degrees Celsius.
100 g water x (102 g NaNO3 / 100 g water) = 102 g NaNO3
This means that 102 grams of NaNO3 is the maximum amount that can dissolve in 100 grams of water at 50 degrees Celsius.
3. Compare the amount of NaNO3 actually present in the solution (1 gram) to the maximum amount that can dissolve (102 grams).
Since the amount of NaNO3 in the solution (1 gram) is much less than the maximum amount that can dissolve (102 grams), the solution is unsaturated.
I hope that helps! Let me know if you have any more questions.
Well, let's break it down. If this solution were at a higher temperature, we might expect it to be saturated because more solute can dissolve in hot water. However, at 20°C, we're dealing with a relatively lower temperature. So, if a solution contains the maximum amount of solute that can dissolve at a given temperature, it's saturated. If it contains less than that maximum amount, it's unsaturated. And if it somehow contains more, it's supersaturated.
Now, if you remember your chemistry, sodium nitrate (NaNO3) is highly soluble in water, so we might be led to believe that we have a supersaturated solution here. But, if I had to bet on it, I'd say this solution is just unsaturated. After all, it's not exceeding the maximum amount of solute that can dissolve at this temperature. So in conclusion, I'm going with unsaturated. But don't worry, even if I'm wrong, I won't dissolve under the pressure!
To determine if the solution is saturated, unsaturated, or supersaturated, we need to compare the amount of solute (NaNO3) dissolved in the solvent (water) with the maximum amount that can dissolve at that temperature (20°C).
In this case, we are given that the solution contains 120 g of NaNO3 in 100 g of water at 20°C. To find out if this amount is saturated, we can calculate the solubility of NaNO3 at 20°C.
The solubility of NaNO3 in water varies with temperature. Let's assume that at 20°C, the solubility of NaNO3 is 100 g per 100 g of water. This means that 100 g of NaNO3 can dissolve in 100 g of water at 20°C.
Now we compare this solubility with the given amount of NaNO3 in 100 g of water. If the given amount (120 g) is less than or equal to the solubility (100 g), then the solution is saturated because all of the NaNO3 has dissolved.
In this case, since 120 g of NaNO3 is greater than the assumed solubility of 100 g, the solution is unsaturated. It means that there is still room for more NaNO3 to dissolve at 20°C.
It may not be liked, A solution of NaNO3 contains 1 gram of solute. At 50oC, this solution is (unsaturated, saturated, supersaturated?)
*HINT: (50, 1)*