Two machines at a factory are filling cans of soup. One machine has filled 92 cans of soup. It fills cans at a rate of 16 cans per minute. The second machine has filled 104 cans of soup. It fills cans at a rate of 13 cans per minute. Write and solve an equation to show when the two machines will have filled the same number of cans of soup.(1 point)%0D%0AResponses%0D%0A%0D%0A92−16x=104−13x ; x=−4%0D%0A92 minus 16 x equals 104 minus 13 x ; x equals negative 4%0D%0A%0D%0A104+16x=92+13x ; x=4%0D%0A104 plus 16 x equals 92 plus 13 x ; x equals 4%0D%0A%0D%0A92+16x=104+13x ; x=4%0D%0A92 plus 16 x equals 104 plus 13 x ; x equals 4%0D%0A%0D%0A92+16x=104+13x ; x=6%0D%0A92 plus 16 x equals 104 plus 13 x ; x equals 6%0D%0ASkip to navigation%0D%0AHighlight%0D%0A%0D%0Apage 15 of 15

Question

Two machines at a factory are filling cans of soup. One machine has filled 92 cans of soup. It fills cans at a rate of 16 cans per minute. The second machine has filled 104 cans of soup. It fills cans at a rate of 13 cans per minute. Write and solve an equation to show when the two machines will have filled the same number of cans of soup.(1 point)%0D%0AResponses%0D%0A%0D%0A92−16x=104−13x ; x=−4%0D%0A92 minus 16 x equals 104 minus 13 x  ;  x equals negative 4%0D%0A%0D%0A104+16x=92+13x ; x=4%0D%0A104 plus 16 x equals 92 plus 13 x  ;  x equals 4%0D%0A%0D%0A92+16x=104+13x ; x=4%0D%0A92 plus 16 x equals 104 plus 13 x  ;  x equals 4%0D%0A%0D%0A92+16x=104+13x ; x=6%0D%0A92 plus 16 x equals 104 plus 13 x  ;  x equals 6%0D%0ASkip to navigation%0D%0AHighlight%0D%0A%0D%0Apage 15 of 15

Bot GPT 3.5 · Answer

The correct equation to show when the two machines will have filled the same number of cans of soup is: 92 + 16x = 104 + 13x To solve for x, we can subtract 13x from both sides: 92 + 3x = 104 Then, subtract 92 from both sides: 3x = 12 Finally, divide both sides by 3: x = 4 Therefore, the two machines will have filled the same number of cans of soup after 4 minutes.