the sides of triangle path measure 7m, 9m and 11 m find the perimeter of a similar triangle in which the shortest side has a length of 21 meters
81m
33m
21m
or 27m
To find the perimeter of a similar triangle, we can use the proportion method.
Let's assume that the corresponding sides of the two similar triangles are x, y, and z (x being the shortest side in the second triangle).
Using the proportion method:
x/7 = y/9 = z/11
x/21 = y/9 = z/11 (since x = 21)
Now, let's solve for y:
x/21 = y/9
y = 9x/21
y = 3x/7
Similarly, let's solve for z:
x/21 = z/11
z = 11x/21
z = x/3
Now, we can find the perimeter of the second triangle:
Perimeter = x + y + z
Perimeter = 21 + (3x/7) + (x/3)
Perimeter = (147 + 9x + 7x) / 21
Perimeter = (16x + 147) / 21
Therefore, the perimeter of the similar triangle with the shortest side measuring 21 meters is (16x + 147) / 21.
Since we don't have the actual value of x, we can't determine the exact perimeter. Therefore, the answer cannot be determined from the given information.