The sides of a triangular path measure 7 m, 9 m, and 11 m. Find the perimeter of a similar triangle in which the shortest side has a length of 21 meters.
81 m
33 m
21 m
27 m
To find the perimeter of a triangle similar to the given triangle, we need to find the ratio of their corresponding side lengths.
For the given triangle, the shortest side is 7 m and the corresponding side of the similar triangle is 21 m. The ratio of these sides is 21/7 = 3.
Therefore, the ratio of the perimeters of the two triangles will be equal to the ratio of their corresponding side lengths. Since the shortest side of the similar triangle is 21 m, its perimeter will be 3 times the perimeter of the given triangle.
The perimeter of the given triangle is 7 + 9 + 11 = 27 m.
So, the perimeter of the similar triangle is 3 * 27 = 81 m.
Therefore, the answer is 81 m.