The point P is located at (-4, 0). It is translated 3 units right and 6 units down to make point P'. What is the location of point P'?(1 point)
Responses
(−1, 6)
(−1, 6)
(−1, −6)
(−1, −6)
(−7, −6)
(−7, −6)
(−7, 6)
To find the location of point P', we need to add the translation values to the coordinates of point P.
Translation 3 units right means adding 3 to the x-coordinate of point P.
Translation 6 units down means subtracting 6 from the y-coordinate of point P.
Starting with point P at (-4, 0):
Adding 3 to the x-coordinate gives: -4 + 3 = -1
Subtracting 6 from the y-coordinate gives: 0 - 6 = -6
Therefore, the location of point P' is (-1, -6).