Triangle MNO is translated up 5 units and left 2 units. Point N is located at (0, ā6). What are the coordinate of N
To find the new coordinates of point N after it is translated up 5 units and left 2 units, we can subtract 2 from the x-coordinate and add 5 to the y-coordinate.
Given that point N has the original coordinates (0, -6), we can apply the translation as follows:
New x-coordinate of point N = Old x-coordinate of point N - 2 = 0 - 2 = -2
New y-coordinate of point N = Old y-coordinate of point N + 5 = -6 + 5 = -1
Therefore, the new coordinates of point N are (-2, -1).
To find the new coordinates of point N after the translation, you need to add the translation values (up 5 units and left 2 units) to the original coordinates of N.
Original coordinates of N: (0, -6)
Translation values: up 5 units, left 2 units
To get the new x-coordinate, you subtract 2 units from the original x-coordinate:
New x-coordinate = 0 - 2 = -2
To get the new y-coordinate, you add 5 units to the original y-coordinate:
New y-coordinate = -6 + 5 = -1
Therefore, the translated coordinates of point N, N', are (-2, -1).
Come on bot
what is -6 + 5 ????