Triangle MNO is translated up 5 units and left 2 units. Point N is located at (0, -6). What are the coordinates of N'?
To translate a point up 5 units, add 5 to the y-coordinate. To translate a point left 2 units, subtract 2 from the x-coordinate.
Since point N is located at (0, -6), we can apply the translation as follows:
- Add 5 to the y-coordinate: -6 + 5 = -1
- Subtract 2 from the x-coordinate: 0 - 2 = -2
Therefore, the coordinates of N' are (-2, -1).
To find the coordinates of N' after the translation, we need to add the translation values to the original coordinates of N.
Given that the triangle was translated up 5 units and left 2 units, we can calculate the new coordinates of N' as follows:
Y-coordinate of N' = Y-coordinate of N + Upward translation
= -6 + 5
= -1
X-coordinate of N' = X-coordinate of N + Leftward translation
= 0 - 2
= -2
Therefore, the coordinates of N' are (-2, -1).