What is the smallest positive integer value of x where y=2^x is greater than y=4x+7 ?
A. x=4
B.x=5
C.x=6
d.x=7
To find the smallest positive integer value of x where y=2^x is greater than y=4x+7, we can set the equations equal to each other and solve for x.
2^x > 4x + 7
Since we want to find the smallest positive integer value of x, we can start by plugging in small values of x to see if the inequality holds true.
For x=1:
2^1 = 2 > 4(1) + 7 = 11 (not true)
For x=2:
2^2 = 4 > 4(2) + 7 = 15 (not true)
For x=3:
2^3 = 8 > 4(3) + 7 = 19 (true)
Therefore, the smallest positive integer value of x where y=2^x is greater than y=4x+7 is x=3.
Answer: D. x=3