The smallest positive integer value of n for which 99 n is a multiple of 24
99 = 3*33
24 = 3*2^3
so, what do you think?
Help me
I think 99π is multiple of 24 which is 8
Find the smallest possible integer value of n for which 99n is multiple of 24
Find the smallest possible integer value of π for which 99π is a multiple 24
To find the smallest positive integer value of n for which 99n is a multiple of 24, we need to find the value of n that makes 99n divisible by 24 without any remainder.
To determine if a number is divisible by 24, we need to check if it is divisible by both 8 and 3.
First, let's check if the number is divisible by 8. For a number to be divisible by 8, the last three digits of the number should be divisible by 8. In this case, the last two digits of 99n will be divisible by 8.
Now let's check if the number is divisible by 3. To find if a number is divisible by 3, we need to add up the digits of the number. In this case, we need to add up the digits of 99n.
The sum of the digits of 99 is 9 + 9 = 18. Since 18 is divisible by 3, we can conclude that 99n is divisible by 3.
So, we have determined that 99n is divisible by both 8 and 3. To find the smallest positive integer value of n, we need to find the least common multiple (LCM) of 8 and 3, which is 24.
Therefore, the smallest positive integer value of n for which 99n is a multiple of 24 is n = 24.