Two fertilizers are applied to randomly selected potato plants. After several weeks, the potatoes are weighed. The weights in kilograms are as follows. Which fertilizer is generally more effective?
Fertilizer A: 27, 20, 16, 18, 22, 19, 23, 21, 17, 19
Fertilizer B: 28, 19, 18, 21, 24, 20, 25, 27, 29, 21
(1 point)
Responses
Fertilizers A and B are both ineffective, because there is no difference in the ranges of the weights of the potatoes.
Fertilizers A and B are both ineffective, because there is no difference in the ranges of the weights of the potatoes.
Fertilizer A is generally more effective, because the mean and median weights of the potatoes treated with it are higher.
Fertilizer A is generally more effective, because the mean and median weights of the potatoes treated with it are higher.
Fertilizer B is generally more effective, because the mean and median weights of the potatoes that were treated with it are higher.
Fertilizer B is generally more effective, because the mean and median weights of the potatoes that were treated with it are higher.
Fertilizers A and B are equally effective, because the ranges of the weights of the potatoes are the same.
Fertilizers A and B are equally effective, because the ranges of the weights of the potatoes are the same.
To determine which fertilizer is generally more effective, we need to compare the mean and median weights of the potatoes treated with each fertilizer.
For Fertilizer A, the mean weight can be calculated by adding up all the weights and dividing by the number of potatoes:
Mean weight of Fertilizer A = (27 + 20 + 16 + 18 + 22 + 19 + 23 + 21 + 17 + 19) / 10 = 202 / 10 = 20.2 kg
To calculate the median weight for Fertilizer A, we need to arrange the weights in ascending order:
16, 17, 18, 19, 19, 20, 21, 22, 23, 27
Since there are an even number of weights, the median is the average of the two middle values: (19 + 20) / 2 = 19.5 kg
For Fertilizer B, the mean weight can be calculated in the same way:
Mean weight of Fertilizer B = (28 + 19 + 18 + 21 + 24 + 20 + 25 + 27 + 29 + 21) / 10 = 232 / 10 = 23.2 kg
Again, we need to arrange the weights in ascending order to calculate the median for Fertilizer B:
18, 19, 20, 21, 21, 24, 25, 27, 28, 29
The two middle values are 21 and 24, so the median is (21 + 24) / 2 = 22.5 kg
From the calculations, it can be observed that the mean weight for Fertilizer B (23.2 kg) is higher than the mean weight for Fertilizer A (20.2 kg). Similarly, the median weight for Fertilizer B (22.5 kg) is higher than the median weight for Fertilizer A (19.5 kg).
Therefore, we can conclude that Fertilizer B is generally more effective, as the average and middle weights of the potatoes treated with it are higher.