Two fertilizers are applied to randomly selected potato plants. After several weeks, the potatoes are weighed. The weights in kilograms are as follows. Which fertilizer is generally more effective?
Fertilizer A: 27, 20, 16, 18, 22, 19, 23, 21, 17, 19
Fertilizer B: 28, 19, 18, 21, 24, 20, 25, 27, 29, 21
To determine which fertilizer is generally more effective, we can compare the average weight of the potatoes for each fertilizer.
For Fertilizer A:
Mean = (27+20+16+18+22+19+23+21+17+19)/10 = 20.2 kg
For Fertilizer B:
Mean = (28+19+18+21+24+20+25+27+29+21)/10 = 22.3 kg
From this calculation, we can see that Fertilizer B had a higher average potato weight than Fertilizer A. Therefore, we would conclude that Fertilizer B is generally more effective.
To determine which fertilizer is generally more effective, we can compare the average weights of the potato plants treated with each fertilizer.
To find the average weight of the potato plants treated with Fertilizer A, we add up all the weights and divide the sum by the number of potato plants:
Average weight for Fertilizer A = (27 + 20 + 16 + 18 + 22 + 19 + 23 + 21 + 17 + 19) / 10 = 202 / 10 = 20.2 kilograms
Next, we find the average weight of the potato plants treated with Fertilizer B:
Average weight for Fertilizer B = (28 + 19 + 18 + 21 + 24 + 20 + 25 + 27 + 29 + 21) / 10 = 232 / 10 = 23.2 kilograms
Comparing the average weights, we can see that the potato plants treated with Fertilizer B generally have a higher average weight (23.2 kilograms) compared to those treated with Fertilizer A (20.2 kilograms). Therefore, Fertilizer B is generally more effective.