Assuming the polynomial below is factorable, choose all the positive values for "b". x^2+bx-20
19
15
1
-1
8
-8
-19
To determine the positive values for "b" for which the polynomial is factorable, we need to find the factors of the constant term -20 (the product of the coefficients of the highest and lowest degree terms).
The factors of -20 are: -1, -2, -4, -5, -10, 1, 2, 4, 5, 10
Let's now check which of these factors, when added or subtracted, yield a positive value for "b" when multiplied by the coefficient of the x term (in this case, 1).
-1 * 1 = -1 (not positive)
-2 * 1 = -2 (not positive)
-4 * 1 = -4 (not positive)
-5 * 1 = -5 (not positive)
-10 * 1 = -10 (not positive)
1 * 1 = 1 (positive)
2 * 1 = 2 (positive)
4 * 1 = 4 (positive)
5 * 1 = 5 (positive)
10 * 1 = 10 (positive)
Therefore, the positive values for "b" are: 1, 2, 4, 5, and 10.
To summarize, the correct positive values for "b" are: 1, 2, 4, 5, 10.