Find the solution of the system of equations.
minus, 2, x, minus, 3, y, equals, minus, 28
−2x−3y=
−28
minus, 2, x, plus, 2, y, equals, 22
−2x+2y=
22
We can solve this system of equations using the method of substitution.
From the first equation, we can isolate x by subtracting 2x from both sides of the equation, and isolate y by subtracting 3y from both sides of the equation:
-2x - 3y = -28
-2x + 2y = 22
Simplifying these equations, we have:
-2x = -28 + 3y
-2x = 22 - 2y
Now we can set these two equations equal to each other and solve for y:
-28 + 3y = 22 - 2y
3y + 2y = 22 + 28
5y = 50
y = 10
Now that we have the value of y, we can substitute it back into one of the original equations to solve for x. Let's use the first equation:
-2x - 3(10) = -28
-2x - 30 = -28
-2x = -28 + 30
-2x = 2
x = -1
The solution to the system of equations is x = -1 and y = 10.