The sides of a square all have a side length of y
. Write a simplified area function in terms of y
for a rectangle whose length is twice the side length of the square and whose width is 2 units longer than the side length of the square.
Part A: Express both the length and the width of the rectangle as a function of a side of the square.
Let y be the side length of the square.
The length of the rectangle is twice the side length of the square, so it is 2y.
The width of the rectangle is 2 units longer than the side length of the square, so it is y + 2.
Therefore, the length and the width of the rectangle as functions of the side of the square are:
Length of the rectangle = 2y
Width of the rectangle = y + 2
Part B: Write a function to represent the area of the rectangle in terms of the sides of the square. (1 point)
Responses
A(s)=6y+4
cap A times s is equal to 6 y plus 4
A(s)=2y3+2y2
cap A times s is equal to 2 y cubed plus 2 y squared
A(s)= 2y2+4y
A(s)= 2y2+4y
A(s)=2y2+4
cap A times s is equal to 2 y squared plus 4
A(s)=3y+2
The correct function to represent the area of the rectangle in terms of the side length of the square is:
A(s) = 2y^2 + 4y