A bowling ball is traveling at 6 m/s when it hits a pin. If the bowling ball has a mass of 6 kilograms, how much kinetic energy does it have when it hits the pin?
36 J
42 J
108 J
216 J
The kinetic energy (KE) of an object is given by the formula KE = 1/2 * mass * velocity^2.
Plugging in the values given:
KE = 1/2 * 6 kg * (6 m/s)^2
KE = 1/2 * 6 kg * 36 m^2/s^2
KE = 108 kg*m^2/s^2
Therefore, the bowling ball has 108 Joules (J) of kinetic energy when it hits the pin.
The correct answer is 108 J.