Which of the following shows the correct process of solving ◂+▸−◂⋅▸4(3+120)+150 by generating an equivalent expression using the Zero Power Rule? (1 point) Responses ◂...▸◂+▸−◂⋅▸4(3+120)+150 ◂=⋯▸=◂+▸−4(15)+15=−60+15=−45 negative 4 left parenthesis 3 plus 12 superscript 0 baseline right parenthesis plus 15 superscript 0 baseline equals negative 4 left parenthesis 15 right parenthesis plus 15 equals negative 60 plus 15 equals negative 45 ◂=⋯▸◂+▸−◂⋅▸4(3+120)+150=−◂⋅▸4(3+1)+1=−4⋅4+1=−16+1=−15 negative 4 left parenthesis 3 plus 12 superscript 0 baseline right parenthesis plus 15 superscript 0 baseline equals negative 4 left parenthesis 3 plus 1 right parenthesis plus 1 equals negative 4 times 4 plus 1 equals negative 16 plus 1 equals negative 15 ◂=⋯▸◂+▸−◂⋅▸4(3+120)+150=◂+▸−4(15)+1=−60+1=−59 negative 4 left parenthesis 3 plus 12 superscript 0 baseline right parenthesis plus 15 superscript 0 baseline equals negative 4 left parenthesis 15 right parenthesis plus 1 equals negative 60 plus 1 equals negative 59 ◂=⋯▸◂+▸−◂⋅▸4(3+120)+150=−◂⋅▸4(3+1)+1=−4⋅4+1=−4⋅5=−20
The correct process of solving ◂+▸−◂⋅▸4(3+120)+150 by generating an equivalent expression using the Zero Power Rule is:
◂=⋯▸=◂+▸−4(15)+15=−60+15=−45