A roller-coaster is at the top of a 62-meter hill. The car and its passengers have a total mass of 1,088 kilograms. By the time the car reaches the bottom of the hill, its speed is 74 miles per hour (33 meters per second). How much kinetic energy does the car have at the bottom of the hill? K E= 1/2m^2
To calculate the kinetic energy (KE), we can use the formula KE = 1/2 * m * v^2, where m is the mass of the car and its passengers, and v is the velocity of the car.
Given:
Mass (m) = 1088 kg
Velocity (v) = 33 m/s
Plugging in these values into the formula, we have:
KE = 1/2 * 1088 kg * (33 m/s)^2
KE = 1/2 * 1088 kg * 1089 m^2/s^2
KE = 59392 kg * m^2/s^2
Therefore, the car has a kinetic energy of 59,392 kilogram meters squared per second squared (kg * m^2/s^2) at the bottom of the hill.