A cyclist rode her bicycle 10 1/2 miles on Monday, 12 7/8 miles on Tuesday, and 11 4/5 miles on Wednesday. Compute the total distance for the three days.
Group of answer choices
35 9/40 miles
35 7/40 miles
24 7/40 miles
34 7/40 miles
To solve this problem, first, find the sum of the three distances:
10 1/2 + 12 7/8 + 11 4/5
To add the fractions, find a common denominator:
10 1/2 + 12 7/8 + 11 4/5 = 10 4/8 + 12 7/8 + 11 4/5
Convert each fraction to an equivalent fraction with a denominator of 40:
10 4/8 = 10 20/40
12 7/8 = 12 35/40
11 4/5 = 11 32/40
Now add the numbers and fractions separately:
10 + 12 + 11 = 33
20/40 + 35/40 + 32/40 = 87/40
Combine the whole number and fraction:
33 + 87/40
To add a whole number and a fraction, convert the whole number to a fraction with a denominator of 40:
33 = 1320/40
1320/40 + 87/40 = 1407/40
Divide the numerator by the denominator to simplify:
1407 ÷ 40 = 35 remainder 7
The final answer is:
35 7/40 miles
Therefore, the total distance for the three days is 35 7/40 miles.