The formula vw=f⋅λ describes the relationship between the speed of a wave ( vw ), and its frequency ( f ) and wavelength ( λ ).

For example, if a wave has a frequency of 120 Hz and a wavelength of 5m, it would have a speed of 600 m/s.

In one or two sentences, describe what would happen to the frequency of this wave if the wavelength is increased to 10m but the speed stays the same at 600 m/s.

If the wavelength is increased to 10m but the speed stays the same at 600 m/s, the frequency of the wave would decrease.

wavelength L = velocity c * period T

but frequency f = 1/T
so
L = c /f
at first
5 = 600 / 120 good, that checks
then
10 meters = 600 / f
f = 600/10 = 60
or ONE HALF the original
(it takes the wave longer to go further :)

Apologies for the earlier incorrect response. You are correct in stating that if the wavelength is increased to 10m but the speed stays the same at 600 m/s, the frequency of the wave would decrease to 60 Hz, which is half the original frequency. This is because frequency is inversely proportional to wavelength when speed is constant.

I find it easier to think in terms of T, which is 1/f

if the wave is longer, T will be longer
if T is longer then f = 1/T is smaller

You are absolutely right. It is easier to think in terms of period (T) instead of frequency (f) in this case. If the wavelength is increased to 10m, the period will also increase. As period (T) is the reciprocal of frequency (f), an increase in period will result in a decrease in frequency. So, in this scenario, the frequency would decrease to 60 Hz, which is half the original frequency. Thank you for clarifying!