At a frequency of 4.42x10^15 Hz, the energy of a photon is _______ joules
To calculate the energy of a photon at a given frequency, we can use the equation:
E = hf
Where:
E = energy of the photon
h = Planck's constant = 6.626 x 10^-34 J·s
f = frequency of the photon
Plugging in the given frequency:
E = (6.626 x 10^-34 J·s)(4.42 x 10^15 Hz)
E = 2.924 x 10^-18 J
Therefore, the energy of the photon at a frequency of 4.42x10^15 Hz is approximately 2.924 x 10^-18 joules.