Grade 12 Chemistry.
A photon that has a frequency of 5.11 x 1014 Hz has an energy of_______________J of energy.
Show your steps
To calculate the energy of a photon, we can use the equation:
E = hf
Where:
E is the energy of the photon
h is Planck's constant (6.626 x 10^-34 J·s)
f is the frequency of the photon
Substituting the given values:
E = (6.626 x 10^-34 J·s)(5.11 x 10^14 Hz)
E = 3.38186 x 10^-19 J
Therefore, the energy of the photon is 3.38186 x 10^-19 J.
To find the energy of a photon, you can use the equation:
E = hf
Where E is the energy, h is the Planck's constant (6.626 x 10^-34 J·s), and f is the frequency of the photon.
Step 1: Write down the given frequency.
Given frequency: 5.11 x 10^14 Hz
Step 2: Use the Planck's constant to calculate the energy.
E = (6.626 x 10^-34 J·s)(5.11 x 10^14 Hz)
Step 3: Multiply the values.
E = 3.38 x 10^-19 J
Therefore, a photon with a frequency of 5.11 x 10^14 Hz has an energy of 3.38 x 10^-19 J.
To calculate the energy of a photon, you can use the equation:
E = h * ν
Where E represents the energy of the photon, h is Planck's constant (6.63 x 10^-34 J·s), and ν is the frequency of the photon.
Given:
ν = 5.11 x 10^14 Hz
Let's substitute the given values into the equation:
E = (6.63 x 10^-34 J·s) * (5.11 x 10^14 Hz)
Now, we can multiply the values:
E = (6.63 x 10^-34) * (5.11 x 10^14)
To simplify, we can multiply the coefficients and add the exponents:
E = 33.8793 x 10^-20 J
Finally, we can express the answer in proper scientific notation:
E ≈ 3.39 x 10^-19 J
Therefore, the energy of the photon is approximately 3.39 x 10^-19 J.