Ammonium nitrate dissolves in water via the following reaction:%0D%0A%0D%0ANH4NO3(s) → NH4+(aq) + NO3-(aq)%0D%0A%0D%0AThe bond energies of the compounds in the reaction are as follows:%0D%0A%0D%0ANH4NO3 = 3040%0D%0A3040%0D%0A kJ/mol%0D%0ANH4+ = 1564%0D%0A1564%0D%0A kJ/mol%0D%0ANO3- = 1009%0D%0A1009%0D%0A kJ/mol%0D%0AHow much total energy does the reaction have, and how will the environment change when the reaction occurs?%0D%0A%0D%0A(1 point)%0D%0AResponses%0D%0A%0D%0A467%0D%0A467%0D%0A kJ/mol; lose heat%0D%0A467 kJ/mol; lose heat%0D%0A%0D%0A−467%0D%0A−%0D%0A467%0D%0A kJ/mol; lose heat%0D%0Anegative 467 kJ/mol; lose heat%0D%0A%0D%0A−467%0D%0A−%0D%0A467%0D%0A kJ/mol; gain heat%0D%0Anegative 467 kJ/mol; gain heat%0D%0A%0D%0A467%0D%0A467%0D%0A kJ/mol; gain heat%0D%0A467 kJ/mol; gain heat%0D%0ASkip to navigation%0D%0AHighlight
The total energy of the reaction can be calculated by summing the bond energies of the reactants and subtracting the bond energies of the products:
Total energy = (Energy of NH4NO3) - (Energy of NH4+) - (Energy of NO3-)
Total energy = (3040 kJ/mol) - (1564 kJ/mol) - (1009 kJ/mol)
Total energy = 467 kJ/mol
Therefore, the total energy of the reaction is 467 kJ/mol.
When the reaction occurs, the environment will lose heat because the reaction is exothermic.