Triangle ABC%0D%0A%0D%0A%0D%0A%0D%0A has vertices point A (−3,−3)%0D%0A%0D%0A %0D%0A(%0D%0A−%0D%0A3%0D%0A,%0D%0A−%0D%0A3%0D%0A)%0D%0A, point B (5,−3)%0D%0A%0D%0A %0D%0A(%0D%0A5%0D%0A,%0D%0A−%0D%0A3%0D%0A)%0D%0A, and point C (2, 4)%0D%0A%0D%0A %0D%0A(%0D%0A2%0D%0A,%0D%0A %0D%0A4%0D%0A)%0D%0A. Find the coordinates of A′, B′,%0D%0A%0D%0A′%0D%0A,%0D%0A %0D%0A%0D%0A′%0D%0A,%0D%0A and C′%0D%0A%0D%0A′%0D%0A after a dilation with a scale factor of 2 and a center point of dilation at the origin.
To find the coordinates of A', B', and C' after a dilation with a scale factor of 2 and a center point of dilation at the origin, we need to multiply each coordinate by the scale factor.
For point A (-3, -3):
A' = (-3 * 2, -3 * 2)
= (-6, -6)
For point B (5, -3):
B' = (5 * 2, -3 * 2)
= (10, -6)
For point C (2, 4):
C' = (2 * 2, 4 * 2)
= (4, 8)
Therefore, the coordinates of A' are (-6, -6), the coordinates of B' are (10, -6), and the coordinates of C' are (4, 8).