If a triangle with vertices (4, 3), (8, 3), and (7, 5) is translated to the right 4 units and down 2 units, what are the vertices of the translated figure
To translate a figure to the right 4 units, we add 4 to the x-coordinates of each vertex, and to translate it down 2 units, we subtract 2 from the y-coordinates of each vertex.
The original triangle has vertices:
A(4, 3)
B(8, 3)
C(7, 5)
To translate it to the right 4 units, we add 4 to the x-coordinates:
A'(4+4, 3) = A'(8, 3)
B'(8+4, 3) = B'(12, 3)
C'(7+4, 5) = C'(11, 5)
To translate it down 2 units, we subtract 2 from the y-coordinates:
A''(8, 3-2) = A''(8, 1)
B''(12, 3-2) = B''(12, 1)
C''(11, 5-2) = C''(11, 3)
Therefore, the vertices of the translated triangle are:
A'(8, 1)
B'(12, 1)
C''(11, 3)