If a triangle with vertices (4, 3), (8, 3), and (7, 5) is translated to the right 4 units and down 2 units, what are the vertices of the translated figure?(1 point)
The vertices of the translated figure can be found by adding 4 to the x-coordinates and subtracting 2 from the y-coordinates:
(4+4, 3-2) = (8, 1)
(8+4, 3-2) = (12, 1)
(7+4, 5-2) = (11, 3)
So, the vertices of the translated figure are (8, 1), (12, 1), and (11, 3).
To translate a figure, we simply add the specified value to the x-coordinates and the y-coordinates of each vertex.
In this case, we need to translate the triangle 4 units to the right and 2 units down.
Let's perform the translation on each vertex:
Vertex 1: (4, 3)
To translate it 4 units to the right, we add 4 to the x-coordinate: 4 + 4 = 8.
To translate it 2 units down, we subtract 2 from the y-coordinate: 3 - 2 = 1.
So the new coordinates for vertex 1 are (8, 1).
Vertex 2: (8, 3)
To translate it 4 units to the right, we add 4 to the x-coordinate: 8 + 4 = 12.
To translate it 2 units down, we subtract 2 from the y-coordinate: 3 - 2 = 1.
So the new coordinates for vertex 2 are (12, 1).
Vertex 3: (7, 5)
To translate it 4 units to the right, we add 4 to the x-coordinate: 7 + 4 = 11.
To translate it 2 units down, we subtract 2 from the y-coordinate: 5 - 2 = 3.
So the new coordinates for vertex 3 are (11, 3).
Therefore, the vertices of the translated triangle are (8, 1), (12, 1), and (11, 3).