Write the expression (4x2) 6(2x+7) in the standard form of a quadratic expressic
x²+bx+c. What are the values of the coefficients of each term and the constant te
A=
b=
C=
The expression can be simplified as follows:
(4x^2)(6(2x+7))
= (4x^2)(12x + 42)
= 48x^3 + 168x^2
In the standard form of a quadratic expression, ax^2 + bx + c, we can see that the highest degree term is x^3, so the coefficient of that term is a = 48.
The next highest degree term is x^2, so the coefficient of that term is b = 168.
There is no constant term in this expression, so c = 0.
Therefore:
A = 48
b = 168
c = 0