Write the expression (4x-2)•6(2x+7) in standard form of a quadratic expression, ax^2 +bx +c. What are the values of the coefficients of each and the constant term?
To find the standard form of the quadratic expression, we need to simplify the given expression and collect like terms.
The given expression is: (4x - 2)(6)(2x + 7)
Using the distributive property, we can expand this expression:
= (4x - 2)(6)(2x + 7)
= 24x(2x + 7) - 12(2x + 7)
= 48x^2 + 168x - 24x - 84
Collecting like terms, we have:
= 48x^2 + (168x - 24x) - 84
= 48x^2 + 144x - 84
So, in standard form, the expression is: 48x^2 + 144x - 84
The coefficient of the x^2 term is 48, the coefficient of the x term is 144, and the constant term is -84.