Ammonia gas has a molar mass of approximately 17 grams per mole. At 290K and 1.2 atm, a sample of ammonia has a volume of 3.7 L. In three to five sentences, explain how you can find the mass of the ammonia. Then, given R=0.0821L⋅atmmol⋅K , calculate the mass.
To find the mass of the ammonia gas, we can use the ideal gas law equation: PV = nRT. By rearranging the equation, we can solve for the number of moles (n) of the gas: n = PV / RT. In this case, P is the pressure (1.2 atm), V is the volume (3.7 L), R is the ideal gas constant (0.0821 L⋅atm/mol⋅K), and T is the temperature in Kelvin (290K). Once we find the number of moles, we can multiply it by the molar mass of ammonia (17 g/mol) to obtain the mass. In this case, the mass of the ammonia is approximately 5.13 grams.
make it sound like a 10th grader wrote it
To figure out the mass of the ammonia gas, we need to use an equation called the ideal gas law. It goes like this: PV = nRT. Don't worry, I'll explain what all those letters mean! P is the pressure, V is the volume, R is a special number called the ideal gas constant, and T is the temperature. So, we plug in the numbers we have: the pressure is 1.2 atm, the volume is 3.7 liters, the temperature is 290 Kelvin, and the ideal gas constant is 0.0821 L⋅atm/mol⋅K. After doing some math, we find that the number of moles (n) is about 0.279. To find the mass, we just multiply the number of moles by the molar mass of ammonia, which is 17 grams/mol. So, the mass of the ammonia is around 4.74 grams.
