Jada has challenged herself to do at least 100 full push-ups this week. On Sunday, she does 30 push-ups. Her arms are sore, so she decides to do fewer push-ups on the remaining days of the week. She wants to do the same number of push-ups each day for the rest of the week. Write and solve an inequality for the number of push-ups Jada needs to do each day for the rest of the week to meet her goal of 100 push-ups. Which answer choice best interprets the solution in the context of the problem?(1 point)
Responses
Jada needs to do at least 12 push-ups each day for the rest of the week to meet her goal.
Jada needs to do at least 12 push-ups each day for the rest of the week to meet her goal.
Jada needs to do push-ups for at least 12 more days to meet her goal.
Jada needs to do push-ups for at least 12 more days to meet her goal.
Jada needs to do at least 14 push-ups each day for the rest of the week to meet her goal.
Jada needs to do at least 14 push-ups each day for the rest of the week to meet her goal.
Jada needs to do at least 10 push-ups each day for the rest of the week to meet her goal.
Let X be the number of push-ups Jada needs to do each day for the rest of the week.
On Sunday, Jada did 30 push-ups.
For the rest of the week, Jada needs to do push-ups for 7 - 1 = <<7-1=6>>6 days.
Jada's total goal is 100 push-ups.
From the problem, we can create the inequality 30 + 6X ≥ 100.
Subtracting 30 from both sides of the inequality, we get 6X ≥ 70.
Dividing both sides by 6, we get X ≥ 70/6, which simplifies to X ≥ 11.6666666667.
Since Jada cannot do a fraction of a push-up, she needs to do at least 12 push-ups each day for the rest of the week to meet her goal.
Therefore, the answer choice that best interprets the solution in the context of the problem is:
Jada needs to do at least 12 push-ups each day for the rest of the week to meet her goal.