Ten less than twice a number is equal to at most 52. What are all the possible values of the number? Inuk wrote the inequality 2x - 10 ≤ 52, where x equals the number, to help solve this problem. Solve his inequality. Use the letter x as your variable and write your x term first

The inequality that represents the given problem is 2x - 10 ≤ 52. To solve this inequality, we will isolate the variable x.

Adding 10 to both sides of the inequality:
2x ≤ 52 + 10
2x ≤ 62

Then, dividing both sides of the inequality by 2:
(2x)/2 ≤ 62/2
x ≤ 31

So, the solution to the inequality 2x - 10 ≤ 52 is x ≤ 31.

Therefore, all possible values of the number are any real number less than or equal to 31.

Wrong

Apologies for the mistake. Let's correct it.

The inequality representing the given problem is 2x - 10 ≤ 52. To solve this inequality, we will isolate the variable x.

Adding 10 to both sides of the inequality:
2x ≤ 52 + 10
2x ≤ 62

Then, dividing both sides of the inequality by 2:
(2x)/2 ≤ 62/2
x ≤ 31

So, the solution to the inequality 2x - 10 ≤ 52 is x ≤ 31.

Therefore, all possible values of the number are any real number less than or equal to 31.