Ten less than twice a number is equal to at least 52. What are the possible values of the number? Write an inequality that could be used to solve this problem. Use the letter x as the variable, and write the inequality so that the x term comes first. (1 point)
1. 2x - 10 ≥ 52
2. 11 + 3/4x < 112
3. 5x + 50 ≥ 63
rest of the answers:
4. x ≤ 31
5. x ≥ 4
Questions for the quick check:
1. (1/3n) + 4.5 ≤ 38.9, where n is equal to the number
2. 2d + 3 ≥ 15
3. n ≤ 103.5
4. n > 45
5. w ≥ 8.6
100% right I got everything right
Let's break down the problem step by step:
Step 1: "Ten less than twice a number" can be written as: 2x - 10.
Step 2: "is equal to at least 52" can be written as: ≥ 52.
Step 3: Combining the expressions from step 1 and step 2, we get: 2x - 10 ≥ 52.
Therefore, the inequality that could be used to solve this problem is: 2x - 10 ≥ 52.
i will come back with the answers for the quick check!!
To solve this problem, we need to translate the given sentence into an inequality.
Let's break down the given sentence:
"Ten less than twice a number" can be represented as 2x - 10.
"is equal to at least 52" means that the given expression is greater than or equal to 52.
So, the inequality that represents the given sentence is:
2x - 10 ≥ 52.
To solve this inequality for the possible values of the number (x), we can follow these steps:
1. Add 10 to both sides of the inequality to isolate the x term: 2x ≥ 62.
2. Divide both sides of the inequality by 2 to get the value of x: x ≥ 31.
Therefore, the possible values of the number in the inequality 2x - 10 ≥ 52 are x ≥ 31.