Graph the quadratic y=4x2+3x−8 . What is the vertex of this quadratic?(1 point) Responses
(−0.375,−8.563)
(0,−8)
(1.088,0)
(−1.838,0)
To find the vertex of the quadratic, we first need to find the axis of symmetry. The axis of symmetry is the vertical line that passes through the vertex and is given by the formula x = -b/2a, where a and b are the coefficients of the quadratic equation.
In this case, the quadratic equation is y = 4x^2 + 3x - 8, so a = 4 and b = 3.
The x-coordinate of the vertex can be found by using the formula x = -b/2a:
x = -3/(2*4) = -3/8 = -0.375
Now, to find the y-coordinate of the vertex, we substitute the x-coordinate back into the quadratic equation:
y = 4*(-0.375)^2 + 3*(-0.375) - 8 = -8.563
Therefore, the vertex of the quadratic is (-0.375, -8.563).
The correct answer is (−0.375,−8.563).