Graph the quadratic y=4x2+3x−8 . What is the vertex of this quadratic?(1 point) Responses (1.088,0) left parenthesis 1.088 comma 0 right parenthesis (−0.375,−8.563) left parenthesis negative 0.375 comma negative 8.563 right parenthesis (−1.838,0) left parenthesis negative 1.838 comma 0 right parenthesis (0,−8)
To find the vertex of a quadratic function in the form y = ax^2 + bx + c, we can use the formula x = -b / (2a) to find the x-coordinate of the vertex.
In this case, a = 4 and b = 3.
x = -b / (2a) = -3 / (2*4) = -3/8
To find the y-coordinate of the vertex, we substitute the x-coordinate into the equation:
y = 4(-3/8)^2 + 3(-3/8) - 8
= 9/16 - 9/8 - 8
= 9/16 - 18/16 - 128/16
= -137/16
Therefore, the vertex is (-3/8, -137/16), which is approximately (-0.375, -8.563).
So the correct answer is (−0.375,−8.563) left parenthesis negative 0.375 comma negative 8.563 right parenthesis.